根据逆矩阵的定义。 由于 分块矩阵 满足矩阵的加法乘法运算。故设其逆矩阵，分块相同。与原矩阵作矩阵乘法，使求得矩阵为 单位矩阵。 不过对于大多数分块，这种操作并. Abc=a (bc) 但矩阵运算没有乘法交换律，并且大多数情况下， ab \ne ba.
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